(2x-1)^2=3x+8

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Solution for (2x-1)^2=3x+8 equation: 



(2x-1)^2=3x+8

We move all terms to the left:

(2x-1)^2-(3x+8)=0

We get rid of parentheses

(2x-1)^2-3x-8=0

We add all the numbers together, and all the variables

-3x+(2x-1)^2-8=0

We move all terms containing x to the left, all other terms to the right

-3x+(2x-1)^2=8

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